F(x)=1/5(x+3)^2-7

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Solution for F(x)=1/5(x+3)^2-7 equation: 



(F)=1/5(F+3)^2-7

We move all terms to the left:

(F)-(1/5(F+3)^2-7)=0



Domain of the equation: 5(F+3)^2-7)!=0

F∈R



We multiply all the terms by the denominator


F*5(F+3)^2-7)-(1=0

We add all the numbers together, and all the variables

F*5(F+3)^2=0

Wy multiply elements

5F^2(F=0

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